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And you can verify that because all of these other terms have an x minus a here. It is going to be equal to zero. Can we bound this and if we are able to bound this, if we're able to figure out an upper bound on its magnitude-- So actually, what we want to do is, we wanna bound its overall magnitude. This is going to be equal to zero. Take the third derivative of y is equal to x squared. And if we assume that this is higher than degree one, we know that these derivates are going to be the same at a. I'm literally just taking the N plus oneth derivative of both sides of this equation right over here.

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